Our study of electricity begins with electrostatics and the electrostatic force. This is one of the four fundamental forces of nature. The electrostatic force is nicely modeled by Coulomb’s Law. We use Coulomb’s Law to find the forces created by nearby charges.

Electrostatics deals with forces between charges. Static means the charges are not moving, or at least are not moving very fast.

How fast is “not very fast”?

When a charge is in motion, it generates a magnetic field. The magnetic field creates a magnetic force. As we begin our study of electricity, we want to keep things really simple and focus on just electric force. So we have charges sit still, or move very slowly. Therefore, “not very fast” means so slow the magnetic effects are insignificant compared to the electric force.

Written by Willy McAllister.



Where does electric force come from? The answer is, it comes from charge. But how do we know there is such a thing as charge? The concept of charge comes from observing nature. Under certain conditions (like when you rub a balloon on your sweater) we see forces between objects. To explain those forces we came up with the idea that objects had a property called charge.

Charge is a lot like gravity, it is a force that “acts at a distance.” This is a pretty mind-blowing concept. Also, the existence of charge, “Electric force comes from charge, and we know charge exists because we see electric force”, seems quite circular, and it is. However, it is the best story we’ve been able to come up with, and it allows us to do so many magical and impressive things with electricity.

Electric forces are very large, far greater than the force of gravity. There is only one type of gravity; gravity only attracts. Unlike gravity, there are two types of electric charge. We call them positive and negative.

Unlike charges attract, (we use the variable $q$ or $Q$ to represent charge)

Unlike charges attract

Like charges repel,

Like charges repel

Coulomb - the unit of charge

When we want to attach a number to an amount of charge, the unit we use is the coulomb, abbreviated with a capital $\text C$. If you want to learn about this unit, take a quick side trip to this article.

Coulomb’s Law of electric force

Coulomb’s Law very nicely models the force between two charged objects,

$\vec F = \dfrac{1}{4\pi\epsilon_0} \,\dfrac{q_0\, q_1}{r^2} \,\bold{\hat r}$


  • $\vec F$ is the electric force. The force is a vector. It acts along a direct line between the two charged bodies. The force is measured in newtons.
  • $q_0$ and $q_1$ are the amount of charge on each object, measured in coulombs.
  • $r$ is the distance between the charged objects, measured in meters.
  • $\bold{\hat r}$ is a unit vector (a vector of length $1$) that points from one charge towards the other. It turns the right side into a vector quantity. $\bold{\hat r}$ reminds us the force acts along the line between the two charges.
  • $\dfrac{1}{4\pi\epsilon_0}$ is a constant of proportionality. It relates the units on the left side (newtons) to the units on the right side (coulombs and meters). We need a constant because we want the answer come out with the right value given the system of units we use to measure force, charge, and distance (newtons, coulombs, meters).

$\epsilon_0$ permittivity of free space

The constant in front of Coulomb’s Law looks rather complicated. Why is it like that? The Greek letter $\epsilon_0$ is known as the permittivity of free space, (free space is a vacuum).

This notation comes from a theory you learn later called Gauss’s Flux Theorem. Gauss’s flux theorem tells us the constant at the front of Coulomb’s Law actually has two parts, a geometric factor and another factor contributed by the experimental setup.

Gauss’s theorem involves the surface area of a sphere. The geometric factor $4\pi$ is the total solid angle of a sphere (just like $2\pi$ is the total angle of a circle). This is where the $4\pi$ term comes from.

The other part of the constant represents the experimental setup where all the units are matched up properly. We capture this in the $\epsilon_0$ term.

This notation for the constant allows Gauss’s Law to be written in a particularly simple form. It is worth it to bring this form all the way back here to the beginning of electrostatics, which is why it shows up in Coulomb’s Law.

The constant $\epsilon_0$ is the conversion factor for the experimental setup and the system of units you use to measure force. In the SI system of units, ${\epsilon_0}$ is,

$\epsilon_0 = 8.854 187 817 \times 10^{-12}$ coulomb$^2/$newton-meter$^2$

The first person to measure $\epsilon_0$ was Coulomb himself, which is why we use his name for the unit of charge.

This value of $\epsilon_0$ means,

$\dfrac{1}{4\pi \epsilon_0} = \dfrac{1}{4\pi \cdot 8.854 \times 10^{-12}} = 8.987 \times 10^9$

For engineering purposes, we round this to something easier to remember,

$\dfrac{1}{4\pi \epsilon_0} = 9 \times 10^{9}$ newton-meter$^2$/coulomb$^2$

Some textbooks give this number a name, $K$. You will see $K$ and $\epsilon_0$ notation used in different charge problems, so be ready for both. Coulomb’s Law can be written,

$\vec F = 9 \times 10^{9} \dfrac{q_0\,q_1}{r^2}\,\bold{\hat r}$

Example - two point charges

Find the electric force between two point charges, $+3\,\mu\text C$ and $-50\,\text{nC}$ positioned $2\,\text{cm}$ apart.

Two point charges

The force is predicted by Coulomb’s Law. We always do these sorts of problems in two steps.

  • First, figure out the direction of the force.
  • Second, figure out the magnitude of the force.


The direction of the force can be found by inspection. The electric force always acts along the line between the two point charges. For this problem, the charges have opposite signs, so we know they attract. We add force vectors to the diagram,

Two point charges with attractive force


The magnitude of the force comes from Coulomb’s Law. We use the absolute value of the charges (since we already figured out the direction),

$|\vec F| = 9 \times 10^9 \,\dfrac{|q_0|\, |q_1|}{r^2}$

We don’t have to use vector notation since we already know the direction. And for the same reason we use the absolute value of the charges. Fill in the values we know and crank the arithmetic,

$|\vec F| = 9 \times 10^{9} \,\dfrac{\text{Nm}^2}{\text C^2} \,\,\dfrac{3\,\mu\text C\cdot 50\,\text{nC}}{(2\,\text{cm})^2}$

Expanding the numbers to scientific notation,

$|\vec F| = 9 \times 10^{9} \,\dfrac{\text{Nm}^2}{\text C^2} \,\,\dfrac{3\times 10^{-6}\text C\cdot 50\times 10^{-9}\text{C}}{(0.02\,\text m)^2}$

Cancel the units and compute the force,

$|\vec F| = 9 \times 10^{9} \,\dfrac{\text N\cancel\text m^2}{\cancel{\text C^2}} \,\,\dfrac{150\times 10^{-15}\,\cancel\text C^2}{4\times 10^{-4}\,\cancel{\text m^2}}$

$|\vec F| = 3.37\times 10^{-3}\,\text N$

And we assemble the answer by combining the direction and magnitude of the force. The two charges are being pulled together with a force of $3.37\times 10^{-3}\,\text N$,

Two point charges with attractive force shown


The electric force always acts along the straight line between the two charges.

Coulomb’s Law predicts the force between two point charges,

$\vec F = \dfrac{1}{4\pi\epsilon_0}\,\dfrac{q_0\, q_1}{r^2} \,\bold{\hat r}$

$\epsilon_0 = 8.85 \times 10^{-12}$ coulomb$^2/$newton-meter$^2$

$\dfrac{1}{4\pi \epsilon_0} = 9 \times 10^{9}$ newton-meter$^2$/coulomb$^2$

$\epsilon_0$ is the permittivity of free space.

When working on electric force problems we usually do it in two steps,

  • Figure out the direction of the force based on the sign of the charges.
  • Figure out the magnitude of the force using the absolute value of the charges.

Then combine the direction and magnitude to get a force vector. Doing it this way avoids errors that often happen if you include signs and vector directions into the Coulomb’s Law equation.


Kip, A. H. (1969), Fundamentals of Electricity and Magnetism (2nd edition, McGraw-Hill)